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Ask and you shall receive
Ask and you shall receive
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Ask and you shall receive
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30-01-2013, 12:15 PM
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Ask and you shall receive
New policy: If you ask to get banned, you get banned.
The only type of people who say, "BAN ME BRO I DARE YOU LOL" are immature assholes who will probably get banned for something else eventually. They will never contribute to the community and they will never grow up. They think they can outsmart the administration by using reverse psychology and stick around longer by asking to be banned. I think our mods are smart enough to see through this horseshit, but to speed things up I think it should just be a policy: ask to be banned, and you shall be banned. Not to be confused with someone who is worried about being banned because of bad experiences at other forums. This is for the passive aggressive types who try the reverse psychology or "I dare you bro!" bullshit. It's a good policy that has served well on many other forums that has an extremely low false positive rate (it *only* catches trolls and people on their way to being banned anyway). E 2 = (mc 2)2 + (pc )2 614C → 714N + e– + ̅νe 2 K(s) + 2 H2O(l) → 2 KOH(aq) + H2 (g) + 196 kJ/mol It works, bitches. |
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4 users Like Phaedrus's post |
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30-01-2013, 12:19 PM
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RE: Ask and you shall receive
I kinda of like this idea, personally.
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30-01-2013, 12:27 PM
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RE: Ask and you shall receive
I don't approve of this. People should be banned only for violating the rules upon which they agreed with their registration on this forum.
![[Image: 7oDSbD4.gif]](http://i.imgur.com/7oDSbD4.gif)
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30-01-2013, 12:30 PM
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RE: Ask and you shall receive
(30-01-2013 12:27 PM)Vosur Wrote: I don't approve of this. People should be banned only for violating the rules upon which they agreed with their registration on this forum. Yes. Which is why it is written into the rules of hundreds of forums. E 2 = (mc 2)2 + (pc )2 614C → 714N + e– + ̅νe 2 K(s) + 2 H2O(l) → 2 KOH(aq) + H2 (g) + 196 kJ/mol It works, bitches. |
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30-01-2013, 12:31 PM
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RE: Ask and you shall receive
(30-01-2013 12:27 PM)Vosur Wrote: I don't approve of this. People should be banned only for violating the rules upon which they agreed with their registration on this forum.Nah, if they ask to be banned, I say give it to them. It's the generous thing to do. Skepticism is not a position; it is an approach to claims. Science is not a subject, but a method. ![[Image: flagstiny%206.gif]](http://www.acbeddoe.com/photos/flagstiny%206.gif)
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2 users Like Chas's post |
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30-01-2013, 12:32 PM
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RE: Ask and you shall receive
Do we even have written rules? I can't find them.
E 2 = (mc 2)2 + (pc )2 614C → 714N + e– + ̅νe 2 K(s) + 2 H2O(l) → 2 KOH(aq) + H2 (g) + 196 kJ/mol It works, bitches. |
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30-01-2013, 01:04 PM
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RE: Ask and you shall receive
(30-01-2013 12:32 PM)Phaedrus Wrote: Do we even have written rules? I can't find them.Rules If I ask for Jessie J.... do I get Jessie J? For no matter how much I use these symbols, to describe symptoms of my existence. You are your own emphasis. So I say nothing. -Bemore. |
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1 user Likes bemore's post |
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30-01-2013, 01:06 PM
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RE: Ask and you shall receive
(30-01-2013 01:04 PM)bemore Wrote: Rules No, you get slapped. Best and worst of Ferdinand ..... Best Ferdinand: We don't really say 'theist' in Alabama. Here, you're either a Christian, or you're from Afghanistan and we fucking hate you. Worst Ferdinand: Everyone from British is so, like, fucking retarded. |
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2 users Like Hughsie's post |
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30-01-2013, 01:06 PM
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RE: Ask and you shall receive
(30-01-2013 12:30 PM)Phaedrus Wrote: Yes. Which is why it is written into the rules of hundreds of forums....but not into the rules of this one.
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30-01-2013, 01:09 PM
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RE: Ask and you shall receive
(30-01-2013 01:06 PM)Vosur Wrote:Rules which are currently under revision anyway.(30-01-2013 12:30 PM)Phaedrus Wrote: Yes. Which is why it is written into the rules of hundreds of forums....but not into the rules of this one. Vosur, free speech and being an asshat troll are two different things. I understand your concerns, but for the sake of this forum, sometimes people need to get kicked. Sorry. E 2 = (mc 2)2 + (pc )2 614C → 714N + e– + ̅νe 2 K(s) + 2 H2O(l) → 2 KOH(aq) + H2 (g) + 196 kJ/mol It works, bitches. |
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1 user Likes Phaedrus's post |
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