Strange sum (riddle tread)
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13-02-2012, 07:36 AM
RE: Strange sum (riddle tread)
Here's a puzzle:

How do distribute 6 cubes of sugar into 3 teacups such that each teacup contains at least one cube of sugar, and each cup has an odd number of sugar cubes?

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13-02-2012, 07:44 AM
RE: Strange sum (riddle tread)
(13-02-2012 07:36 AM)robotworld Wrote:  Here's a puzzle:

How do distribute 6 cubes of sugar into 3 teacups such that each teacup contains at least one cube of sugar, and each cup has an odd number of sugar cubes?

Eat 3 sugar cubes and then place 1 of the remaining 3 in each teacup? Put one in each teacup with hot tea, drink the tea and then place 1 in each teacup? Or how about fusing 3 sets of 2 sugar cubes by getting them wet and then making them solidify again?

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13-02-2012, 07:52 AM
RE: Strange sum (riddle tread)
Do you consider 1.5 an odd number? Tongue
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13-02-2012, 08:16 AM (This post was last modified: 13-02-2012 08:17 AM by robotworld.)
RE: Strange sum (riddle tread)
(13-02-2012 07:52 AM)Zat Wrote:  Do you consider 1.5 an odd number? Tongue

No Tongue The sugar cubes must be whole Big Grin
(13-02-2012 07:44 AM)Azaraith Wrote:  
(13-02-2012 07:36 AM)robotworld Wrote:  Here's a puzzle:

How do distribute 6 cubes of sugar into 3 teacups such that each teacup contains at least one cube of sugar, and each cup has an odd number of sugar cubes?

Eat 3 sugar cubes and then place 1 of the remaining 3 in each teacup? Put one in each teacup with hot tea, drink the tea and then place 1 in each teacup? Or how about fusing 3 sets of 2 sugar cubes by getting them wet and then making them solidify again?

Interesting solution, but the cubes must be in pristine condition Big Grin Great attempt!

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13-02-2012, 08:25 AM (This post was last modified: 13-02-2012 08:26 AM by morondog.)
RE: Strange sum (riddle tread)
put one cube in each cup and crush the remaining ones so that they're not cubes when they are added to the cups?
redefine 2 as an odd number
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13-02-2012, 11:37 AM
RE: Strange sum (riddle tread)
Am I allowed to put one teacup inside another teacup?

If so, let's call the teacups A, B and C. C is the big one.
Put 3 cubes in A, put 1 cube in B and 2 cubes in C. C will have an odd number when you put B inside C.

I don't care if I'm wrong, I'm happy just feeling smug that I can think outside of the teacup.
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13-02-2012, 11:47 AM
RE: Strange sum (riddle tread)
Same as this OP:

3 guys need a hotel room. The rate is $30. They each pay 10 and head to the room. Later the manager realizes he overcharged the men by 5 dollars. He hands 5 ones to the bellhop to bring to them. Stumped as to how to divide 5 dollars between 3 men he decides to give them each 1 dollar and keep the other 2 for himself. Since each man gets 1 dollar back they effectively paid 9 dollars each for the room. 9 x 3 is 27. 27 plus the 2 the bellhop kept is 29. What happened the the last dollar?

I realize reading it might make it easier to solve and those who know the answer obviously won't have any trouble explaining it. But I've stumped dozens of people with this one. They always do the math wrong.

“Whenever you find yourself on the side of the majority, it's time to pause and reflect.”

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13-02-2012, 01:20 PM
RE: Strange sum (riddle tread)
(13-02-2012 11:47 AM)germanyt Wrote:  Same as this OP:

3 guys need a hotel room. The rate is $30. They each pay 10 and head to the room. Later the manager realizes he overcharged the men by 5 dollars. He hands 5 ones to the bellhop to bring to them. Stumped as to how to divide 5 dollars between 3 men he decides to give them each 1 dollar and keep the other 2 for himself. Since each man gets 1 dollar back they effectively paid 9 dollars each for the room. 9 x 3 is 27. 27 plus the 2 the bellhop kept is 29. What happened the the last dollar?

I realize reading it might make it easier to solve and those who know the answer obviously won't have any trouble explaining it. But I've stumped dozens of people with this one. They always do the math wrong.

Being new to this thread, I have been reading it from the start and I think this was posed earlier in the form of 3 ladies buying a TV
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13-02-2012, 01:45 PM (This post was last modified: 13-02-2012 01:52 PM by kim.)
RE: Strange sum (riddle tread)
(13-02-2012 11:47 AM)germanyt Wrote:  Same as this OP:

3 guys need a hotel room. The rate is $30. They each pay 10 and head to the room. Later the manager realizes he overcharged the men by 5 dollars. He hands 5 ones to the bellhop to bring to them. Stumped as to how to divide 5 dollars between 3 men he decides to give them each 1 dollar and keep the other 2 for himself. Since each man gets 1 dollar back they effectively paid 9 dollars each for the room. 9 x 3 is 27. 27 plus the 2 the bellhop kept is 29. What happened the the last dollar?

I realize reading it might make it easier to solve and those who know the answer obviously won't have any trouble explaining it. But I've stumped dozens of people with this one. They always do the math wrong.

Well... each man was only supposed to pay 8.~4 x 3 = 25 actual cost of room + 3 = 28 + the 2 the bell hop took = 30.
Does that solve it?

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13-02-2012, 02:14 PM (This post was last modified: 13-02-2012 02:15 PM by germanyt.)
RE: Strange sum (riddle tread)
(13-02-2012 01:20 PM)DLJ Wrote:  
(13-02-2012 11:47 AM)germanyt Wrote:  Same as this OP:

3 guys need a hotel room. The rate is $30. They each pay 10 and head to the room. Later the manager realizes he overcharged the men by 5 dollars. He hands 5 ones to the bellhop to bring to them. Stumped as to how to divide 5 dollars between 3 men he decides to give them each 1 dollar and keep the other 2 for himself. Since each man gets 1 dollar back they effectively paid 9 dollars each for the room. 9 x 3 is 27. 27 plus the 2 the bellhop kept is 29. What happened the the last dollar?

I realize reading it might make it easier to solve and those who know the answer obviously won't have any trouble explaining it. But I've stumped dozens of people with this one. They always do the math wrong.

Being new to this thread, I have been reading it from the start and I think this was posed earlier in the form of 3 ladies buying a TV

I didn't read it. Just the OP and then hit reply.
(13-02-2012 01:45 PM)kim Wrote:  
(13-02-2012 11:47 AM)germanyt Wrote:  Same as this OP:

3 guys need a hotel room. The rate is $30. They each pay 10 and head to the room. Later the manager realizes he overcharged the men by 5 dollars. He hands 5 ones to the bellhop to bring to them. Stumped as to how to divide 5 dollars between 3 men he decides to give them each 1 dollar and keep the other 2 for himself. Since each man gets 1 dollar back they effectively paid 9 dollars each for the room. 9 x 3 is 27. 27 plus the 2 the bellhop kept is 29. What happened the the last dollar?

I realize reading it might make it easier to solve and those who know the answer obviously won't have any trouble explaining it. But I've stumped dozens of people with this one. They always do the math wrong.

Well... each man was only supposed to pay 8.~4 x 3 = 25 actual cost of room + 3 = 28 + the 2 the bell hop took = 30.
Does that solve it?

Exactly. I get people saying things like, "the bellhop stole it".

“Whenever you find yourself on the side of the majority, it's time to pause and reflect.”

-Mark Twain
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