Talk Nerdy To Me ;)



20122016, 02:05 PM




RE: Talk Nerdy To Me ;)
(19122016 11:12 AM)jennybee Wrote: If you pile it on top of your head, it's a yoga bun Yoga buns on top of my head? Yes. Yes, please! 

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20122016, 02:09 PM




RE: Talk Nerdy To Me ;)
Can a cat be nerdy? Let's find out, shall we????
[/b] Well, it looks like I've proven that not all cats are cool cats....some are nerdy cats. Shakespeare's Comedy of Errors.... on Donald J. Trump: He is deformed, crooked, old, and sere, Illfac’d, worse bodied, shapeless every where; Vicious, ungentle, foolish, blunt, unkind, Stigmatical in making, worse in mind. 

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20122016, 02:20 PM




RE: Talk Nerdy To Me ;)
(20122016 02:09 PM)dancefortwo Wrote: Can a cat be nerdy? Let's find out, shall we???? I think that last one is Kernel's cat 

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20122016, 05:51 PM




RE: Talk Nerdy To Me ;)
 What do you do with a dead chemist?
 Barium "Freedom is the freedom to say that 2+2=4"  George Orwell (in 1984) 

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20122016, 07:32 PM




RE: Talk Nerdy To Me ;)
(20122016 02:09 PM)dancefortwo Wrote: Can a cat be nerdy? Let's find out, shall we???? Oh, hell no, that cat is the demon seed, and someone's arm is about to have parallel lines of ripped flesh in a few seconds. 

20122016, 08:46 PM




RE: Talk Nerdy To Me ;)
*whispers picard is better than kirk
https://www.youtube.com/channel/UCOW_Ioi2wtuPa88FvBmnBgQ my youtube 

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08012017, 12:15 PM




RE: Talk Nerdy To Me ;)
Don't Live each day like it's your last. Live each day like you have 541 days after that one where every choice you make will have lasting implications to you and the world around you. ~ Tim Minchin 

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08012017, 12:47 PM




RE: Talk Nerdy To Me ;)
Don't worry. As long as you hit that wire with the connecting hook at precisely eightyeight miles per hour the instant the lightning strikes the tower... everything will be fine.
There is only one really serious philosophical question, and that is suicide. Camus 

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08012017, 02:35 PM
(This post was last modified: 08012017 02:53 PM by Kernel Sohcahtoa.)




RE: Talk Nerdy To Me ;)
Let G be a group with the general operation *; thus, we can denote this as <G,*>. By the definition of a group, the elements in <G,*> will be associative [a*(b*c)=(a*b)*c.] and will possess an identity element e (for example, a*e=a and e*a=a) along with an inverse (for example, a*a'=e and a'*a=e).
Now, IMO, here's a pretty cool fact: if G is a group and a,b are elements in G, then (ab)^1 (or the inverse of ab) is equal to b^1a^1 (or the inverse of b times the inverse of a). Now, let the operation in G be multiplicative. To prove this, multiply the left side of b^1a^1 by ab. Thus, ab(b^1a^1) =a(bb^1)a^1 (via the associative law of algebra) =aea^1 (note that bb^1= e) =aa^1 (note ae=a) =e. Since the product of ab and b^1a^1 resulted in the identity element e, then this means that ab and b^1a^1 are inverses of each other. Consequently, the inverse of ab is b^1a^1 or (ab)^1=b^1a^1. "I'm fearful when I see people substituting fear for reason." Klaatu, from The Day The Earth Stood Still (1951) 

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08012017, 02:57 PM
(This post was last modified: 08012017 03:35 PM by jennybee.)




RE: Talk Nerdy To Me ;)
(08012017 02:35 PM)Kernel Sohcahtoa Wrote: Let G be a group with the general operation *; thus, we can denote this as <G,*>. By the definition of a group, the elements in <G,*> will be associative [a*(b*c)=(a*b)*c.] and will possess an identity element e (for example, a*e=a and e*a=a) along with an inverse (for example, a*a'=e and a'*a=e). 

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