srdanova math
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29-01-2012, 02:44 AM
RE: srdanova math
Presupposition-Parts number (a) and mobile number (b ) have a contact , the contact is delete
Process:
P1 4-(.0)2=2
P2 4-(.1)2=¤1(2)1¤ image
P3 4-(.2)2=2
P4 4-(.3)2=¤3(1)1¤
P5 4-(.4)2=¤4(0)2¤
   
General form
a-(.0)b=c
a-(.1)b=c
...
a-(.d)b=c
[S19]-subtraction
CM-only form a-(s.0/s.0)b=c , others do not know , axiom
___________________________________________________________________
Presupposition-In the expression a+(.b)c=d , d-(s.0/s.0))11f or d-(s.0/s.0))number (more) from 11f
Process:
P1 3+(.s.0)5=8-(s.0/s.0))118 , 3+(s.0)5>017
P2 5+(.0)5=5-(s.0/s.0))224 , 5+(.0)5>321
...
General form - a+(.b)c=d-(s.0/s.0))11f ,a+(s.b)c>01e
a+(.b)c=d-(s.0/s.0)e , a+(.b)c>f
a+(.b)c=d-(s.0/s.0)efg , a+(.b)c>hij ...
[S20]-right inequality addition
CM-[S20]-know
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29-01-2012, 09:53 AM
RE: srdanova math
(27-01-2012 04:41 PM)Ben Wrote:  Correct me if I'm completely wrong here, cause I really don't understand what he's saying well, but I thought his point was not that current math can't cover these matters, it's that he's found a way to cover it with fewer axioms.

If that's his point then he failed in his very first post. The Peano Postulates and principles of analytic geometry are not only much more concise than anything he's been saying, they are comprehensible.

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29-01-2012, 12:16 PM
Please stop posting ...
(29-01-2012 02:44 AM)msbiljanica Wrote:  Presupposition-Parts number (a) and mobile number (b ) have a contact , the contact is delete
Process:
P1 4-(.0)2=2
P2 4-(.1)2=¤1(2)1¤ image
P3 4-(.2)2=2
P4 4-(.3)2=¤3(1)1¤
P5 4-(.4)2=¤4(0)2¤

General form
a-(.0)b=c
a-(.1)b=c
...
a-(.d)b=c
[S19]-subtraction
CM-only form a-(s.0/s.0)b=c , others do not know , axiom
___________________________________________________________________
Presupposition-In the expression a+(.b)c=d , d-(s.0/s.0))11f or d-(s.0/s.0))number (more) from 11f
Process:
P1 3+(.s.0)5=8-(s.0/s.0))118 , 3+(s.0)5>017
P2 5+(.0)5=5-(s.0/s.0))224 , 5+(.0)5>321
...
General form - a+(.b)c=d-(s.0/s.0))11f ,a+(s.b)c>01e
a+(.b)c=d-(s.0/s.0)e , a+(.b)c>f
a+(.b)c=d-(s.0/s.0)efg , a+(.b)c>hij ...
[S20]-right inequality addition
CM-[S20]-know

Please stop posting until you can clearly state your point.

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Science is not a subject, but a method.
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29-01-2012, 01:02 PM
RE: Please stop posting ...
(29-01-2012 12:16 PM)Chas Wrote:  
(29-01-2012 02:44 AM)msbiljanica Wrote:  Presupposition-Parts number (a) and mobile number (b ) have a contact , the contact is delete
Process:
P1 4-(.0)2=2
P2 4-(.1)2=¤1(2)1¤ image
P3 4-(.2)2=2
P4 4-(.3)2=¤3(1)1¤
P5 4-(.4)2=¤4(0)2¤

General form
a-(.0)b=c
a-(.1)b=c
...
a-(.d)b=c
[S19]-subtraction
CM-only form a-(s.0/s.0)b=c , others do not know , axiom
___________________________________________________________________
Presupposition-In the expression a+(.b)c=d , d-(s.0/s.0))11f or d-(s.0/s.0))number (more) from 11f
Process:
P1 3+(.s.0)5=8-(s.0/s.0))118 , 3+(s.0)5>017
P2 5+(.0)5=5-(s.0/s.0))224 , 5+(.0)5>321
...
General form - a+(.b)c=d-(s.0/s.0))11f ,a+(s.b)c>01e
a+(.b)c=d-(s.0/s.0)e , a+(.b)c>f
a+(.b)c=d-(s.0/s.0)efg , a+(.b)c>hij ...
[S20]-right inequality addition
CM-[S20]-know

Please stop posting until you can clearly state your point.

Yeah, you should really publish your work so that professional mathematicians can review it. None of us here seem qualified to understand it. Sad
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29-01-2012, 01:26 PM (This post was last modified: 30-01-2012 02:01 AM by GirlyMan.)
RE: Please stop posting ...
(29-01-2012 01:02 PM)Ben Wrote:  Yeah, you should really publish your work so that professional mathematicians can review it. None of us here seem qualified to understand it. Sad

He's using his own notation without first grounding or defining it, as such it's just so much gibberish. No journal or conference would even accept such blather for review. ... Well, maybe this one if he could make it more coherent. Wink

(29-01-2012 12:16 PM)Chas Wrote:  Please stop posting until you can clearly state your point.

Why? Instead of trying to interpret it as mathematics, I like to look at it as abstract art.

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29-01-2012, 02:15 PM
RE: Please stop posting ...
(29-01-2012 01:26 PM)GirlyMan Wrote:  
(29-01-2012 12:16 PM)Chas Wrote:  Please stop posting until you can clearly state your point.

Why? Instead of trying to interpret it as mathematics, I like to look at it as abstract art.

You know, I hadn't thought of that. Cool

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30-01-2012, 04:07 AM
RE: srdanova math
Quote:GirlyManHe's using his own notation without first grounding or defining it, as such it's just so much gibberish. No journal or conference would even accept such blather for review. ... Well, maybe this one if he could make it more coherent.
the concepts that exist in the current math notation using an existing, new things to introduce our notation
__________________________________________________________________
Presupposition-Two ( more) addition (left and right inequalities) can be short to write
Process:
P1 3+(.013)4=y , 3+(.013)4>y ,3+(.013)4<y
P2 8+(.228)5=y , 8+(.228)5>y ,8+(.228)5<y
...
General form - a+(.bcd)e=y ,a+(.bcd)e>y , a+(.bcd)e<y
a+(.bcd_e)f=y , a+(.bcd_e)f>y , a+(.bcd_e)f<y ,...
[S21]-function addition
CM-[S21]-does no know
______________________________________________________
Presupposition-Gap number ( value z) is a variable (same value) with the gaps that is constant
Process:
P1 ¤5(2)0¤,¤4(2)1¤,3(2)2¤,¤2(2)3¤,¤1(2)4¤,¤0(2)5¤ --5¤¤(2)

P2 ¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤
¤2(2)0¤,¤1(2)1¤.¤0(2)2¤
¤1(2)0¤,¤0(2)1¤
¤0(2)0¤ --013¤¤(2)


¤2(2)0¤,¤1(2)1¤,¤0(2)2¤
¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤
...
21¤¤(2)

[S22]-variability of z number
CM-[S22]-does no know
__________________________________________--
PDF - http://www.mediafire.com/?jzheej0qu93jjkm
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30-01-2012, 04:02 PM
RE: srdanova math
3^873/93723 99033!980
|0x-2|=12
76>1352
{1,3,5,7,11,...}
11 = 3 -1
2<1 9928365 "22" x^2

just saying

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31-01-2012, 04:16 AM
RE: srdanova math
Presupposition-Translation of gap number in the variability z ( with constant gap ) can addition
(s.0)
Process:
P1 ¤3(2)3¤+(.z)¤4(2)4=6¤¤(2)+(.z)8¤¤(2)=14¤¤(2)
P2 ¤1(6)1(9)1¤+(.z)¤3(6)2(9)1¤=3¤¤(6)(9)+(.z)6¤¤(6)(9)=9¤¤(6)(9)
...
General form ¤a(b)c¤+(.z)¤d(b)e¤=f¤¤(b )+(.z)g¤¤(b )=h¤¤(b ) ...
[S23]-z addition
CM-[S23]-does no know
__________________________________________
Presupposition-Translation of gap number in the variability z ( with constant gap ) can subtraction
(s.0/s.0)
Process:
P1 ¤3(2)3¤-(.z)¤1(2)1=6¤¤(2)-(.z)2¤¤(2)=4¤¤(2)
P2 ¤3(6)2(9)1¤-(.z)¤1(6)1(9)1¤=6¤¤(6)(9)-(.z)3¤¤(6)(9)=3¤¤(6)(9)
...
General form ¤a(b)c¤-(.z)¤d(b)e¤=f¤¤(b )-(.z)g¤¤(b )=h¤¤(b ) ...
[S24]-z subtraction
CM-[S24]-does no know
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31-01-2012, 07:24 AM
RE: srdanova math
a * (1/a) = 1 (a (!=) 0)
a / b = a(1/b)
(a+b) 2 = a 2 + 2ab + b 2
(a+b)(c+d) = ac + ad + bc + bd
a 2 - b 2 = (a+b)(a-b) (Difference of squares)
a 3 (+-) b 3 = (a (+-) b)(a 2(-+) ab + b 2) (Sum and Difference of Cubes)
x 2 + (a+b)x + AB = (x + a)(x + b)
if ax 2 + bx + c = 0 then x = ( -b (+-)sqrt(b 2 - 4ac) ) / 2a (Quadratic Formula)

A = <A1, A2, ..., An>
A = (A1, A2, ..., An)
|A| = sqrt(A1^2 + A2^2 + ... + An^2)
A + B = (A1 + B1, A2 + B2, ..., An + Bn)
Example:
(2, -3) + (0, 1) = (2+0, -3+1) = (2, -2).
(0.1, 2) + (-1, PI) = (0.1 + -1, 2 + PI) = (-0.9, 2+PI)
kA = (kA1, kA2, ..., kAn)
Example:
2(5, -4) = (2*5, 2*-4) = (10, -8)
-3(1, 2) = (-3*1, -3*2) = (-3, -6)
0(3, 1) = (0*3, 0*1) = (0, 0)
1(2, 3) = (1*2, 1*3) = (2, 3)

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