srdanova math



29012012, 02:44 AM




RE: srdanova math
PresuppositionParts number (a) and mobile number (b ) have a contact , the contact is delete
Process: P1 4(.0)2=2 P2 4(.1)2=¤1(2)1¤ image P3 4(.2)2=2 P4 4(.3)2=¤3(1)1¤ P5 4(.4)2=¤4(0)2¤ General form a(.0)b=c a(.1)b=c ... a(.d)b=c [S19]subtraction CMonly form a(s.0/s.0)b=c , others do not know , axiom ___________________________________________________________________ PresuppositionIn the expression a+(.b)c=d , d(s.0/s.0))11f or d(s.0/s.0))number (more) from 11f Process: P1 3+(.s.0)5=8(s.0/s.0))118 , 3+(s.0)5>017 P2 5+(.0)5=5(s.0/s.0))224 , 5+(.0)5>321 ... General form  a+(.b)c=d(s.0/s.0))11f ,a+(s.b)c>01e a+(.b)c=d(s.0/s.0)e , a+(.b)c>f a+(.b)c=d(s.0/s.0)efg , a+(.b)c>hij ... [S20]right inequality addition CM[S20]know 

29012012, 09:53 AM




RE: srdanova math
(27012012 04:41 PM)Ben Wrote: Correct me if I'm completely wrong here, cause I really don't understand what he's saying well, but I thought his point was not that current math can't cover these matters, it's that he's found a way to cover it with fewer axioms. If that's his point then he failed in his very first post. The Peano Postulates and principles of analytic geometry are not only much more concise than anything he's been saying, they are comprehensible. "The reality of external objects does not admit of strict proof. On the contrary, however, the reality of the object of our internal sense (of myself and state) is clear immediately through consciousness."  Kant 

2 users Like GirlyMan's post 
29012012, 12:16 PM




Please stop posting ...
(29012012 02:44 AM)msbiljanica Wrote: PresuppositionParts number (a) and mobile number (b ) have a contact , the contact is delete Please stop posting until you can clearly state your point. Skepticism is not a position; it is an approach to claims. Science is not a subject, but a method. 

29012012, 01:02 PM




RE: Please stop posting ...
(29012012 12:16 PM)Chas Wrote:(29012012 02:44 AM)msbiljanica Wrote: PresuppositionParts number (a) and mobile number (b ) have a contact , the contact is delete Yeah, you should really publish your work so that professional mathematicians can review it. None of us here seem qualified to understand it. 

29012012, 01:26 PM
(This post was last modified: 30012012 02:01 AM by GirlyMan.)




RE: Please stop posting ...
(29012012 01:02 PM)Ben Wrote: Yeah, you should really publish your work so that professional mathematicians can review it. None of us here seem qualified to understand it. He's using his own notation without first grounding or defining it, as such it's just so much gibberish. No journal or conference would even accept such blather for review. ... Well, maybe this one if he could make it more coherent. (29012012 12:16 PM)Chas Wrote: Please stop posting until you can clearly state your point. Why? Instead of trying to interpret it as mathematics, I like to look at it as abstract art. "The reality of external objects does not admit of strict proof. On the contrary, however, the reality of the object of our internal sense (of myself and state) is clear immediately through consciousness."  Kant 

3 users Like GirlyMan's post 
29012012, 02:15 PM




RE: Please stop posting ...
(29012012 01:26 PM)GirlyMan Wrote:(29012012 12:16 PM)Chas Wrote: Please stop posting until you can clearly state your point. You know, I hadn't thought of that. Skepticism is not a position; it is an approach to claims. Science is not a subject, but a method. 

30012012, 04:07 AM




RE: srdanova math
Quote:GirlyManHe's using his own notation without first grounding or defining it, as such it's just so much gibberish. No journal or conference would even accept such blather for review. ... Well, maybe this one if he could make it more coherent.the concepts that exist in the current math notation using an existing, new things to introduce our notation __________________________________________________________________ PresuppositionTwo ( more) addition (left and right inequalities) can be short to write Process: P1 3+(.013)4=y , 3+(.013)4>y ,3+(.013)4<y P2 8+(.228)5=y , 8+(.228)5>y ,8+(.228)5<y ... General form  a+(.bcd)e=y ,a+(.bcd)e>y , a+(.bcd)e<y a+(.bcd_e)f=y , a+(.bcd_e)f>y , a+(.bcd_e)f<y ,... [S21]function addition CM[S21]does no know ______________________________________________________ PresuppositionGap number ( value z) is a variable (same value) with the gaps that is constant Process: P1 ¤5(2)0¤,¤4(2)1¤,3(2)2¤,¤2(2)3¤,¤1(2)4¤,¤0(2)5¤ 5¤¤(2) P2 ¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤ ¤2(2)0¤,¤1(2)1¤.¤0(2)2¤ ¤1(2)0¤,¤0(2)1¤ ¤0(2)0¤ 013¤¤(2) ¤2(2)0¤,¤1(2)1¤,¤0(2)2¤ ¤3(2)0¤,¤2(2)1¤,¤1(2)2¤,¤0(2)3¤ ... 21¤¤(2) [S22]variability of z number CM[S22]does no know __________________________________________ PDF  http://www.mediafire.com/?jzheej0qu93jjkm 

30012012, 04:02 PM




RE: srdanova math
3^873/93723 99033!980
0x2=12 76>1352 {1,3,5,7,11,...} 11 = 3 1 2<1 9928365 "22" x^2 just saying 

1 user Likes Leela's post 
31012012, 04:16 AM




RE: srdanova math
PresuppositionTranslation of gap number in the variability z ( with constant gap ) can addition
(s.0) Process: P1 ¤3(2)3¤+(.z)¤4(2)4=6¤¤(2)+(.z)8¤¤(2)=14¤¤(2) P2 ¤1(6)1(9)1¤+(.z)¤3(6)2(9)1¤=3¤¤(6)(9)+(.z)6¤¤(6)(9)=9¤¤(6)(9) ... General form ¤a(b)c¤+(.z)¤d(b)e¤=f¤¤(b )+(.z)g¤¤(b )=h¤¤(b ) ... [S23]z addition CM[S23]does no know __________________________________________ PresuppositionTranslation of gap number in the variability z ( with constant gap ) can subtraction (s.0/s.0) Process: P1 ¤3(2)3¤(.z)¤1(2)1=6¤¤(2)(.z)2¤¤(2)=4¤¤(2) P2 ¤3(6)2(9)1¤(.z)¤1(6)1(9)1¤=6¤¤(6)(9)(.z)3¤¤(6)(9)=3¤¤(6)(9) ... General form ¤a(b)c¤(.z)¤d(b)e¤=f¤¤(b )(.z)g¤¤(b )=h¤¤(b ) ... [S24]z subtraction CM[S24]does no know 

31012012, 07:24 AM




RE: srdanova math
a * (1/a) = 1 (a (!=) 0)
a / b = a(1/b) (a+b) 2 = a 2 + 2ab + b 2 (a+b)(c+d) = ac + ad + bc + bd a 2  b 2 = (a+b)(ab) (Difference of squares) a 3 (+) b 3 = (a (+) b)(a 2(+) ab + b 2) (Sum and Difference of Cubes) x 2 + (a+b)x + AB = (x + a)(x + b) if ax 2 + bx + c = 0 then x = ( b (+)sqrt(b 2  4ac) ) / 2a (Quadratic Formula) A = <A1, A2, ..., An> A = (A1, A2, ..., An) A = sqrt(A1^2 + A2^2 + ... + An^2) A + B = (A1 + B1, A2 + B2, ..., An + Bn) Example: (2, 3) + (0, 1) = (2+0, 3+1) = (2, 2). (0.1, 2) + (1, PI) = (0.1 + 1, 2 + PI) = (0.9, 2+PI) kA = (kA1, kA2, ..., kAn) Example: 2(5, 4) = (2*5, 2*4) = (10, 8) 3(1, 2) = (3*1, 3*2) = (3, 6) 0(3, 1) = (0*3, 0*1) = (0, 0) 1(2, 3) = (1*2, 1*3) = (2, 3) 

1 user Likes Leela's post 
« Next Oldest  Next Newest »

User(s) browsing this thread: 1 Guest(s)