srdanova math



03022012, 07:29 PM




RE: Just stop this nonsense
(03022012 06:18 PM)Chas Wrote:(03022012 06:14 PM)GirlyMan Wrote:(03022012 06:22 AM)Chas Wrote: Please get a competent translator to present an overview of your idea.(03022012 06:22 AM)Chas Wrote: Until then, please just stop this fucking nonsense. Fair enough then. As it was in the beginning is now and ever shall be, world without end. Amen. And I will show you something different from either Your shadow at morning striding behind you Or your shadow at evening rising to meet you; I will show you fear in a handful of dust. 

04022012, 10:33 AM




RE: srdanova math
PresuppositionTwo ( more) opposite subtraction (left and right inequalities) can be short to write
Process: P1 7  (.013)4=y , 7  (.013)4>y ,7  (.013)4<y P2 8  (.228)5=y , 8  (.228)5>y ,8  (.228)5<y ... General form a  (.bcd)e=y ,a  (.bcd)e>y , a  (.bcd)e<y a  (.bcd_e)f=y , a  (.bcd_e)f>y , a  (.bcd_e)f<y ,... [S31]function opposite subtraction CM[S31]does no know __________________________________ PresuppositionTwo ( more) addition the same number can be written in shorted form Process: P1 a+(s.c)a=a×(s.c)2 , a×(s.c)b P2 a+(s.c)a+(s.c)a=a×(s.c)3 , a×(s.c)b P3 a+(s.c)a+(s.c)a+(s.c)a=a×(s.c)4 , a×(s.c)b ... [S32]multiplication CM[S32]know , axiom PresuppositionIn terms a×(s.c)b , b can be number 0 (1) Process: P1 a×(s.c)0 P2 a×(s.c)1 [S32a]multiplicationamendment 

05022012, 08:13 AM




RE: srdanova math
PresuppositionIn terms a×(s.c)b , multiplication
Process: P1 4×(s.0)4=16 P2 4×(s.1)4=13 image P3 4×(s.2)4=10 P4 4×(s.3)4=7 P5 4×(s.4)4=4 P1 ¤1(2)1¤×(s.0)4=¤1(2)2(2)2(2)2(2)1¤ P2 ¤1(2)1¤×(s.1)4=¤1(2)1(2)1(2)1(2)1¤ image P3 ¤1(2)1¤×(s.2)4=¤1(1)6(1)1¤ P4 ¤1(2)1¤×(s.3)4=7 P5 ¤1(2)1¤×(s.4)4=¤1(2)1¤ General form a×(s.0)b=c a×(s.1)b=c ... a×(c.d)b=c [S32b]multiplication CM[S32b]know a×(s.0)b other do not know , forms withuut any gaps numbers not known 

05022012, 10:59 PM




RE: srdanova math
Welcome to science. You're gonna like it here  Phil Plait Have you ever tried taking a comfort blanket away from a small child?  DLJ 

4 users Like robotworld's post 
06022012, 10:39 AM




RE: srdanova math
PDF  http://www.mediafire.com/?ffy4ravu1gw4xkd
___________________________________________ PresuppositionThe numbers are multiplication , where a contact is deleted Process: P1 4 × (s.0)4=¤4(0)4(0)4(0)4¤ P2 4 × (s.1)4=¤3(1)2(1)2(1)3¤ image P3 4 × (s.2)4=¤2(6)2¤ P4 4 × (s.3)4=¤1(5)1¤ P5 4 × (s.4)4=0 General form a × (s.0)b=c a × (s.1)b=c ... a × (c.d)b=c [S29]multiplication subtraction CM[S29]does no know ×You will see a sign in the PDF 

07022012, 02:09 AM




RE: srdanova math
(06022012 10:39 AM)msbiljanica Wrote: PDF  http://www.mediafire.com/?ffy4ravu1gw4xkd Still lost at you point... 

07022012, 08:50 AM




RE: srdanova math
PresuppositionThe numbers are multiplication , contact remains the rest is deleted
Process: P1 4 × (s.0)4=0 P2 4 × (s.1)4=¤1(2)1(2)1¤ image P3 4 × (s.2)4=6 P4 4 × (s.3)4=5 P5 4 × (s.4)4=4 General form a × (s.0)b=c a ×(s.1)b=c ... a × (s.d)b=c [S30]multiplication opposite subtraction CM[S30]does no know 

07022012, 09:18 AM




RE: srdanova math
I have a BA in math and I don't understand a single word/symbol of what you are writing... msbiljanica have you also google translated your math? That would explain a lot. You need to take 810 steps back and start with the basics and explain in detail what the fuck you are talking about. Your notation makes no sense. For your convenience I will Google translate this for you, so you can see it is no fucking help to do so. But of course you won't be able to understand the translation, because google translate is shit.
google translation: Имам дипломирао математику и ја не разумем једну реч / симбол онога што пише ... мсбиљаница имате и Гоогле превести вашу математику? То би објаснило доста. Треба да се предузму кораке 810 назад и почети са основама, а детаљно објасните шта јеботе причате. Ваша нотација нема смисла. Ради ваше удобности сам ће Гоогле транслате то за вас, тако да можете да видите да није јебени помоћи да то учине. Али, наравно, нећете бити у стању да разумеју језик, јер је Гоогле Транслате је срање. 

08022012, 03:55 AM




RE: srdanova math
(07022012 09:18 AM)Jakel Wrote: I have a BA in math and I don't understand a single word/symbol of what you are writing... msbiljanica have you also google translated your math? That would explain a lot. You need to take 810 steps back and start with the basics and explain in detail what the fuck you are talking about. Your notation makes no sense. For your convenience I will Google translate this for you, so you can see it is no fucking help to do so. But of course you won't be able to understand the translation, because google translate is shit.I understand you correctly using google translator mathematics is, in fact, all the geometry (the current math, my math), and represents what you see as the ratio of two (more) geometrical object natural axiom  is starting natural along, what is the point, basic rule applies to the relations of the two (more) natural long, so I used pictures that gave the first geometric object (natural along, point) question whether you understand this ? a question for you? have two (more) natural long as the basic rule that you create a new geometric object in space  the first proof of [S3] watch along the infinite, a point that has changed along with the symbols (0), (0.1) ... (0,1,2,3,4,5,6,7,8,9), ... this we get a new geometric object (the numbers along, a set of natural numbers  these two objects are identical, the numbers do not serve us to draw along) [S4] , [S5] everything that follows deals with the relationship alongs and point (number  geometric objects) in number along whether you understand? each along the (number) number along a point, that can be marked as the number along or conversely [S6] , [S7] alongs and points (numbers) can move number along , we get mobile number [S8] 

08022012, 07:56 AM




RE: srdanova math
PresuppositionThree (more) merger (multiplication )
Process: P1 5×(s.3ß3)5=¤1(1)1¤  image P2 5×(s.4ß3)5=¤1(3)1¤  image 5×(s.4ß4)5=¤1(1)1¤ image 5×(s.4ß5)5=1 image P3 5×(s.5ß5)=5 General form a#(s.1ß3)b=c a#(s.2ßd)b=c ... a#(s.eßf)b=c , # calculation operations (×,...) [S31]srki CM[S31]does no know 

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