srdanova math
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10-02-2012, 09:56 AM
RE: srdanova math
So did anyone figure out what the ninja star shuriken meant?
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11-02-2012, 04:50 AM
RE: srdanova math
Presupposition-Srki and gap srki merger (multiplication )
Process:
P1 ¤1(7)1¤=¤1(1)1(1)1(1)1¤×(s.5¤|ß3)6=¤1(1)1(1)1(1)1¤
¤1(1)1(1)1¤=¤1(1)1(1)1(1)¤×(s.5¤|ß4)6=0
P2 4=¤1(1)1(1)1(1)1¤×(s.6¤|ß3)6=2 image
P3 ¤1(1)1(1)1(1)1¤=¤1(1)1(1)1(1)1¤×(s.7¤|ß6)6=¤1(1)1(1)1¤
   
General form
w=a#(s.1¤|ß3)b=c
w=a#(s.2¤|ßd)b=c
...
w=a#(s.e¤|ßf)b=c , #- calculation operations (×,...)

[S33]-two srki
CM-[S33]-does no know
Note - this is a two-way calculation, and therefore has two equals signs left(srki) right(gap srki)
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12-02-2012, 06:10 AM
RE: srdanova math
Presupposition-Subtraction form a-(s.0/s.0)b=0,a-(s.0/s.0)b-(s.0/s.0)b=0 , ...,a-(s.0/s.0)b-
...-(s.0/s.0)b=0 can be written differently counting the subtraction
Process:
P1 12-(..0)4=12 (..c) -counting the subtraction
12-(..1)4=8
12-(..2)4=4
12-(..3)4=0
12:4=3
General form
a-(..0)b=a
a-(..1)b=c
...
a-(..d)b=0
a:b=d

[S34]-counting the subtraction
[S35]-divide
CM-[S34]-does no know ,[S35]-know, axiom
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13-02-2012, 04:29 AM
RE: srdanova math
Presupposition-Subtraction form a-(s.0/s.0)b=0,a-(s.0/s.0)b-(s.0/s.0)b=0 , ...,a-(s.0/s.0)b-
...-(s.0/s.0)b=0, number b can replaced b=((s.0/s.0)c-(s./s.0)d) , b=((s.0/s.0)c-(s.0/s.0)d-
(s./s.0)e),...,b=((s.0/s.0)c-...-(s.0/s.0)w) , can be written differently counting the subtraction
Process:
P1 12-(..0)112=12
12-(..1)112=11
12-(..2)112=9
12-(..3)112=8
12-(..4)112=6
12-(..5)112=5
12-(..6)112=3
12-(..7)112=2
12-(..8)112=0
12:112=8
General form
a-(..0)bef=a
a-(..1)bef=c
...
a-(..d)bef=0
a:bef=d ...
[S36]-inequality divide
CM-[S36]-does no know

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PDF - srdanova math [S36].pdf
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14-02-2012, 04:41 AM
RE: srdanova math
Presupposition-Two ( more) multiplying the same numbers can be for short write
Process:
P1 a×(s.c)a=a^(s.c)2, a^(s.a)b
P2 a×(s.c)a×(s.c)a=a^(s.a)3 , a^(s.a)b
P3 a×(s.c)a×(s.c)a×(s.c)a=a^(s.a)4 ,a^(s.a)b
...
General form
a^(s.a)b
[S37]-graduation
CM-[S37]-know,axiom
__________________________________
Presupposition-In terms a^(s.a)b , b can be number 0 (1)
Process:
P1 a^(s.a)0
P2 a^(s.a)1
[S37a]-graduation -amendment
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14-02-2012, 09:08 PM (This post was last modified: 14-02-2012 09:19 PM by GirlyMan.)
RE: srdanova math
(14-02-2012 04:41 AM)msbiljanica Wrote:  Presupposition-Two ( more) multiplying the same numbers can be for short write
Process:
P1 a×(s.c)a=a^(s.c)2, a^(s.a)b
P2 a×(s.c)a×(s.c)a=a^(s.a)3 , a^(s.a)b
P3 a×(s.c)a×(s.c)a×(s.c)a=a^(s.a)4 ,a^(s.a)b
...
General form
a^(s.a)b
[S37]-graduation
CM-[S37]-know,axiom
__________________________________
Presupposition-In terms a^(s.a)b , b can be number 0 (1)
Process:
P1 a^(s.a)0
P2 a^(s.a)1
[S37a]-graduation -amendment

graduation smells suspiciously like exponentiation, aka repeated multiplication to me. ... meh, probably just my nose.

As it was in the beginning is now and ever shall be, world without end. Amen.
And I will show you something different from either
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14-02-2012, 09:09 PM
RE: srdanova math
This must be the new math I've been hearing about ever since Kindergarten.

It was just a fucking apple man, we're sorry okay? Please stop the madness Laugh out load
~Izel
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14-02-2012, 09:57 PM
RE: srdanova math
Nah what they were talking about way bak then was the invention of the abbaccus.

"I think of myself as an intelligent, sensitive human being with the soul of a clown which always forces me to blow it at the most important moments." -Jim Morrison
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15-02-2012, 07:26 AM
RE: srdanova math
Presupposition-Graduation
Process:
P1- 4^(s.0)5=1024
P2- 4^(s.1)5=769
P3- 4^(s.2)5=514
P4- 4^(s.3)5=259
P5- 4^(s.4)5=4
General form
a^(s.0)b=c
a^(s.1)b=d
...
a^(s.e)b=a
[S37b]-graduation
CM-[S37b]-know a^(s.0)b=c , other do not know
____________________________
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15-02-2012, 08:42 AM
RE: srdanova math
msbiljanica, I applaud your mad persistence. Not only did you tirelessly post your theorems here, but you did the exact same thing, with identical posts, to OH YOU MUST BE KIDDING ME, MORE THAN A HUNDRED FREAKING FORUMS related to science. And from your ability to reply to our posts, you must be human.

If you are a time traveller from the future, you have to understand that the mathematics we use is based on Arabic numerals, with mathematical laws based on old Arabian scholars, or more recently calculus from the 1600s. The mathematical laws you use is unfamiliar to us from the year 2012. Please, tell us why, a paragraph would do, on why would you tell us such theorems from the future.

If you are a just a misunderstood mathematician, it's obvious why. You wouldn't attempt to explain Heisenberg's Uncertainty Principle to a 5 year old who does not have the basic foundations in Physics and Math. Explain in the terms we know, for instance, explaining Heisenberg's Uncertainty Principle to a 5 year old may sound like this:
"Boy, see this ball here? Imagine a smaller ball. Done that? Now, imagine the smallest ball possible, so small you cannot see with your eyes. Ok, this very, very tiny ball you imagined, let's call it Mr. Electron. Mr. Electron is like Superman, a superhero, but his superpower is different. His position always changes - sometimes here, sometimes there. This is to prevent bad guys from hitting him with bullets, you see. But remember, Mr Electron is very, very small, and his ability is thus stronger due to his size. We have the same superpowers as Mr Electron, but we are so large compared to Mr. Electron, that our powers are not as strong as Mr Electron, in fact very, very weak."

It takes time to explain. We will be very interested in what you say, provided that you can put it in terms a layman from the year 2012 can understand.

Did I just write all this? Yes, for I'm really curious in what you are trying to say.

Welcome to science. You're gonna like it here - Phil Plait

Have you ever tried taking a comfort blanket away from a small child? - DLJ
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